What will happen when you attempt to compile and run the following code?

Last Updated on June 24, 2022 by Admin

What will happen when you attempt to compile and run the following code?

#include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
#include <set>
using namespace std;
int 
main()
{
   int mynumbers[] = { 3, 9, 0, 2, 1, 4, 5 };      
   vector < int > v1 (mynumbers, mynumbers + 7); 
   deque < int > d1 (mynumbers, mynumbers + 7); 
   set < int > s1 (mynumbers, mynumbers + 7);   
   vector < int >::iterator found = find (v1.begin (), v1.end (), 3);  //LINE I
   if (found != v1.end ())    //LINE II   
      cout << "found" << ", ";   
   cout << find (d1.begin (), d1.end (), 9) << ", ";    //LINE III
   cout << find (s1.begin (), s1.end (), 6);   //LINE IV
   return 0;
}

• compilation error in LINE II
• compilation error in LINE III
• the program outputs 3, 9, 6
• the program outputs found, 9, 6
• compilation error in LINE IV
• the exception will be thrown at LINE I
• compilation error in LINE I
• the program outputs found, 9,