What will happen when you attempt to compile and run the code below, assuming that file test.out do not exist before the program execution?

Last Updated on December 6, 2021 by Admin 2

What will happen when you attempt to compile and run the code below, assuming that file test.out do not exist before the program execution?

#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
using namespace std;

template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<val<<” “; } };

int main (){
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f(“test.out”);
list<int> l(t, t+10);
for_each(l.begin(), l.end(), Out<int>(f));
f.close();
return 0;
}

  • file test.out will be created and opened for writing
  • file test.out will be created and opened for reading
  • no file will be created nor opened
  • file test.out will contain sequence 1 2 3 4 5 6 7 8 9 10
  • compilation error
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