Last Updated on May 1, 2022 by Admin 2
What happens if you try to compile and run this program?
#include <stdio.h> int main(void) { int i = -1, j = 1; for(i++; i++; i++) j++; printf("%d", i + j); return 0; }
- the program outputs
2
- the program outputs
1
- the program outputs enters an infinite loop and outputs nothing
- the program outputs
3