Last Updated on July 31, 2021 by Admin 3
Examine the diagram below:
Based on the diagram and the following partial output from Router R2, which networks will be present in the routing table of Router R1?
- 192.168.5.0
- 10.0.0.0
- 172.50.0.0
- 192.168.5.0 and 10.0.0.0
Explanation:
The routes that will be present in Router R1 are 192.168.5.0 and 10.0.0.0. According to the output, only the route from EIGRP 55 will be redistributed to EIGRP 200. Therefore, the 10.0.0.0 network will be advertised to Router R1 from Router R2 and the 192.168.5.0 network, which is present in the routing table of Router R2, will be advertised to Router R1.The 192.168.5.0 network alone would not be correct. The 10.0.0.0 network will be present as well.The 172.50.0.0 network will not be present because Router 2 is not configured with a redistribution statement for that network. The required statement would be redistribute ospf 1.
The routes that will be present in Router R1 are 192.168.5.0 and 10.0.0.0. According to the output, only the route from EIGRP 55 will be redistributed to EIGRP 200. Therefore, the 10.0.0.0 network will be advertised to Router R1 from Router R2 and the 192.168.5.0 network, which is present in the routing table of Router R2, will be advertised to Router R1.The 192.168.5.0 network alone would not be correct. The 10.0.0.0 network will be present as well.The 172.50.0.0 network will not be present because Router 2 is not configured with a redistribution statement for that network. The required statement would be redistribute ospf 1.
Objective:
Layer 3 Technologies
Sub-Objective:
Configure and verify redistribution between any routing protocols or routing sources